MathematicsMedium244×since 2002Q4427Let A=[21012−10−12]A=\left[\begin{array}{ccc}2 & 1 & 0 \\ 1 & 2 & -1 \\ 0 & -1 & 2\end{array}\right]A=21012−10−12. If ∣adj(adj(adj2A))∣=(16)n|\operatorname{adj}(\operatorname{adj}(\operatorname{adj} 2 A))|=(16)^{n}∣adj(adj(adj2A))∣=(16)n, then nnn is equal to :A9B8C10D12Check answerSkip