MathematicsMedium53×since 2002Q3151Let A = {θ∈(−π2,π):3+2isinθ1−2isinθis purely imaginary}\left\{ {\theta \in \left( { - {\pi \over 2},\pi } \right):{{3 + 2i\sin \theta } \over {1 - 2i\sin \theta }}is\,purely\,imaginary} \right\}{θ∈(−2π,π):1−2isinθ3+2isinθispurelyimaginary} . Then the sum of the elements in A is :A5π6{5\pi \over 6}65πBπ\piπC3π4{3\pi \over 4}43πD2π3{{2\pi } \over 3}32πCheck answerSkip