MathematicsMedium202×since 2002Q5828Let a vector a⃗\vec{a}a has magnitude 9. Let a vector b⃗\vec{b}b be such that for every (x,y)∈R×R−{(0,0)}(x, y) \in \mathbf{R} \times \mathbf{R}-\{(0,0)\}(x,y)∈R×R−{(0,0)}, the vector (xa⃗+yb⃗)(x \vec{a}+y \vec{b})(xa+yb) is perpendicular to the vector (6ya⃗−18xb⃗)(6 y \vec{a}-18 x \vec{b})(6ya−18xb). Then the value of ∣a⃗×b⃗∣|\vec{a} \times \vec{b}|∣a×b∣ is equal to :A939 \sqrt{3}93B27327 \sqrt{3}273C9D81Check answerSkip