MathematicsMedium129×since 2002Q5123Let α\alphaα and β\betaβ be the roots of equation x2−6x−2=0{x^2} - 6x - 2 = 0x2−6x−2=0. If an=αn−βn,{a_n} = {\alpha ^n} - {\beta ^n},an=αn−βn, for n≥1,n \ge 1,n≥1, then the value of a10−2a82a9{{{a_{10}} - 2{a_8}} \over {2{a_9}}}2a9a10−2a8 is equal to :A333B−3- 3−3C666D−6- 6−6Check answerSkip