MathematicsMedium63×since 2002Q3709Let fff and ggg be the twice differentiable functions on R\mathbb{R}R such that f′′(x)=g′′(x)+6xf''(x)=g''(x)+6xf′′(x)=g′′(x)+6x f′(1)=4g′(1)−3=9f'(1)=4g'(1)-3=9f′(1)=4g′(1)−3=9 f(2)=3g(2)=12f(2)=3g(2)=12f(2)=3g(2)=12. Then which of the following is NOT true?Ag(−2)−f(−2)=20g(-2)-f(-2)=20g(−2)−f(−2)=20BThere exists x0∈(1,3/2)x_0\in(1,3/2)x0∈(1,3/2) such that f(x0)=g(x0)f(x_0)=g(x_0)f(x0)=g(x0)C∣f′(x)−g′(x)∣<6⇒−1<x<1|f'(x)-g'(x)| < 6\Rightarrow -1 < x < 1∣f′(x)−g′(x)∣<6⇒−1<x<1DIf −1<x<2-1 < x < 2−1<x<2, then ∣f(x)−g(x)∣<8|f(x)-g(x)| < 8∣f(x)−g(x)∣<8Check answerSkip