MathematicsMedium179×since 2002Q4221Let f(2)=4f(2) = 4f(2)=4 and f′(x)=4.f'(x) = 4.f′(x)=4. Then limx→2xf(2)−2f(x)x−2\mathop {\lim }\limits_{x \to 2} {{xf\left( 2 \right) - 2f\left( x \right)} \over {x - 2}}x→2limx−2xf(2)−2f(x) is given byA222B−2- 2−2C−4- 4−4D333Check answerSkip