MathematicsMedium249×since 2002Q2527Let (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ) be the mirror image of the point (2,3,5)(2,3,5)(2,3,5) in the line x−12=y−23=z−34\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}2x−1=3y−2=4z−3. Then, 2α+3β+4γ2 \alpha+3 \beta+4 \gamma2α+3β+4γ is equal toA32B31C33D34Check answerSkip