Let
m1,m2 be the slopes of two adjacent sides of a square of side a such that
a2+11a+3(m12+m22)=220. If one vertex of the square is
(10(cosα−sinα),10(sinα+cosα)), where
α∈(0,2π) and the equation of one diagonal is
(cosα−sinα)x+(sinα+cosα)y=10, then
72(sin4α+cos4α)+a2−3a+13 is equal to :