MathematicsHard115×since 2008Q4343Let F₁(A, B, C) = (A ∧\wedge∧ ∼\sim∼ B) ∨\vee∨ [∼\sim∼C ∧\wedge∧ (A ∨\vee∨ B)] ∨\vee∨ ∼\sim∼ A and F₂(A, B) = (A ∨\vee∨ B) ∨\vee∨ (B →\to→ ∼\sim∼A) be two logical expressions. Then :ABoth F₁ and F₂ are not tautologiesBF₁ and F₂ both are tautologiesCF₁ is not a tautology but F₂ is a tautologyDF₁ is a tautology but F₂ is not a tautologyCheck answerSkip