MathematicsHard210×since 2002Q3345Let F(x)=f(x)+f(1x),F\left( x \right) = f\left( x \right) + f\left( {{1 \over x}} \right),F(x)=f(x)+f(x1), where f(x)=∫lxlogt1+tdt,f\left( x \right) = \int\limits_l^x {{{\log t} \over {1 + t}}dt,}f(x)=l∫x1+tlogtdt, Then F(e)F(e)F(e) equalsA111B222C1/21/21/2D000Check answerSkip