MathematicsHard175×since 2002Q2636Let f(x)=x2+1x2f\left( x \right) = {x^2} + {1 \over {{x^2}}}f(x)=x2+x21 and g(x)=x−1xg\left( x \right) = x - {1 \over x}g(x)=x−x1, x∈R−{−1,0,1}x \in R - \left\{ { - 1,0,1} \right\}x∈R−{−1,0,1}. If h(x)=f(x)g(x)h\left( x \right) = {{f\left( x \right)} \over {g\left( x \right)}}h(x)=g(x)f(x), then the local minimum value of h(x) isA222\sqrt 222B3C-3D−22-2\sqrt 2−22Check answerSkip