MathematicsEasy210×since 2002Q3393Let f(x) be a differentiable function defined on [0, 2] such that f'(x) = f'(2 −-− x) for all x∈\in∈ (0, 2), f(0) = 1 and f(2) = e². Then the value of ∫02f(x)dx\int\limits_0^2 {f(x)} dx0∫2f(x)dx is :A1 + e²B2(1 + e²)C1 −-− e²D2(1 −-− e²)Check answerSkip