MathematicsHard202×since 2002Q5741Let λ∈R,a⃗=λi^+2j^−3k^,b⃗=i^−λj^+2k^\lambda \in \mathbb{R}, \vec{a}=\lambda \hat{i}+2 \hat{j}-3 \hat{k}, \vec{b}=\hat{i}-\lambda \hat{j}+2 \hat{k}λ∈R,a=λi^+2j^−3k^,b=i^−λj^+2k^. If ((a⃗+b⃗)×(a⃗×b⃗))×(a⃗−b⃗)=8i^−40j^−24k^((\vec{a}+\vec{b}) \times(\vec{a} \times \vec{b})) \times(\vec{a}-\vec{b})=8 \hat{i}-40 \hat{j}-24 \hat{k}((a+b)×(a×b))×(a−b)=8i^−40j^−24k^, then ∣λ(a⃗+b⃗)×(a⃗−b⃗)∣2|\lambda(\vec{a}+\vec{b}) \times(\vec{a}-\vec{b})|^2∣λ(a+b)×(a−b)∣2 is equal to :A136B140C144D132Check answerSkip