MathematicsMedium175×since 2002Q2750Let f(x)=x5+2x3+3x+1,x∈Rf(x)=x^5+2 x^3+3 x+1, x \in \mathbf{R}f(x)=x5+2x3+3x+1,x∈R, and g(x)g(x)g(x) be a function such that g(f(x))=xg(f(x))=xg(f(x))=x for all x∈Rx \in \mathbf{R}x∈R. Then g(7)g′(7)\frac{g(7)}{g^{\prime}(7)}g′(7)g(7) is equal to :A42B7C1D14Check answerSkip