MathematicsHard110×since 2002Q3836Let f,g:R→Rf, g: \mathbf{R} \rightarrow \mathbf{R}f,g:R→R be defined as : f(x)=∣x−1∣ and g(x)={ex,x≥0x+1,x≤0.f(x)=|x-1| \text { and } g(x)= \begin{cases}\mathrm{e}^x, & x \geq 0 \\ x+1, & x \leq 0 .\end{cases}f(x)=∣x−1∣ and g(x)={ex,x+1,x≥0x≤0. Then the function f(g(x))f(g(x))f(g(x)) isAneither one-one nor onto.Bone-one but not onto.Cboth one-one and onto.Donto but not one-one.Check answerSkip