Application of Derivatives — JEE Main 2018 · 16 Apr, Morning shift · Q2638 · Alror
Application of Derivatives
JEE Main 2018 · 16 Apr, Morning shift · Q2638
MathematicsHard175×since 2002Q2638
Let M and m be respectively the absolute maximum and the absolute minimum values of the function, f(x) = 2x³ − 9x² + 12x + 5 in the interval [0, 3]. Then M −m is equal to :