MathematicsMedium129×since 2002Q5167Let S={x∈R:(3+2)x+(3−2)x=10}\mathbf{S}=\left\{x \in \mathbf{R}:(\sqrt{3}+\sqrt{2})^x+(\sqrt{3}-\sqrt{2})^x=10\right\}S={x∈R:(3+2)x+(3−2)x=10}. Then the number of elements in S\mathrm{S}S is :A4B0C2D1Check answerSkip