MathematicsHard202×since 2002Q5818Let a→=αi^+2j^−k^\overrightarrow a = \alpha \widehat i + 2\widehat j - \widehat ka=αi+2j−k and b→=−2i^+αj^+k^\overrightarrow b = - 2\widehat i + \alpha \widehat j + \widehat kb=−2i+αj+k, where α∈R\alpha \in Rα∈R. If the area of the parallelogram whose adjacent sides are represented by the vectors a→\overrightarrow aa and b→\overrightarrow bb is 15(α2+4)\sqrt {15({\alpha ^2} + 4)}15(α2+4), then the value of 2∣a→∣2+(a→ . b→)∣b→∣22{\left| {\overrightarrow a } \right|^2} + \left( {\overrightarrow a \,.\,\overrightarrow b } \right){\left| {\overrightarrow b } \right|^2}2a2+(a.b)b2 is equal to :A10B7C9D14Check answerSkip