MathematicsHard202×since 2002Q5736Let a→,b→,c→\overrightarrow a ,\overrightarrow b ,\overrightarrow ca,b,c three vectors mutually perpendicular to each other and have same magnitude. If a vector r→{ \overrightarrow r }r satisfies. a→×{(r→−b→)×a→}+b→×{(r→−c→)×b→}+c→×{(r→−a→)×c→}=0→\overrightarrow a \times \{ (\overrightarrow r - \overrightarrow b ) \times \overrightarrow a \} + \overrightarrow b \times \{ (\overrightarrow r - \overrightarrow c ) \times \overrightarrow b \} + \overrightarrow c \times \{ (\overrightarrow r - \overrightarrow a ) \times \overrightarrow c \} = \overrightarrow 0a×{(r−b)×a}+b×{(r−c)×b}+c×{(r−a)×c}=0, then r→\overrightarrow rr is equal to :A13(a→+b→+c→){1 \over 3}(\overrightarrow a + \overrightarrow b + \overrightarrow c )31(a+b+c)B13(2a→+b→−c→){1 \over 3}(2\overrightarrow a + \overrightarrow b - \overrightarrow c )31(2a+b−c)C12(a→+b→+c→){1 \over 2}(\overrightarrow a + \overrightarrow b + \overrightarrow c )21(a+b+c)D12(a→+b→+2c→){1 \over 2}(\overrightarrow a + \overrightarrow b + 2\overrightarrow c )21(a+b+2c)Check answerSkip