MathematicsEasy210×since 2002Q3374Let I=∫ab(x4−2x2)dx.{\rm I} = \int\limits_a^b {\left( {{x^4} - 2{x^2}} \right)} dx.I=a∫b(x4−2x2)dx. If I is minimum then the ordered pair (a, b) is -A(2,−2)\left( {\sqrt 2 , - \sqrt 2 } \right)(2,−2)B(0,2)\left( {0,\sqrt 2 } \right)(0,2)C(−2,2)\left( { - \sqrt 2 ,\sqrt 2 } \right)(−2,2)D(−2,0)\left( { - \sqrt 2 ,0} \right)(−2,0)Check answerSkip