MathematicsMedium53×since 2002Q3228Let S={z∈C:zˉ=i(z2+Re(zˉ))}S=\left\{z \in \mathbb{C}: \bar{z}=i\left(z^{2}+\operatorname{Re}(\bar{z})\right)\right\}S={z∈C:zˉ=i(z2+Re(zˉ))}. Then \sum_\limits{z \in \mathrm{S}}|z|^{2} is equal to :A72\frac{7}{2}27B4C3D52\frac{5}{2}25Check answerSkip