MathematicsMedium179×since 2002Q4140Let [t] denote the greatest integer ≤\le≤ t and limx→0x[4x]=A\mathop {\lim }\limits_{x \to 0} x\left[ {{4 \over x}} \right] = Ax→0limx[x4]=A. Then the function, f(x) = [x²]sin(π\piπx) is discontinuous, when x is equal to :AA+1\sqrt {A + 1}A+1BA+5\sqrt {A + 5}A+5CA+21\sqrt {A + 21}A+21DA\sqrt {A}ACheck answerSkip