MathematicsEasy57×since 2003Q3991Let the eccentricity of the hyperbola H:x2a2−y2b2=1H:{{{x^2}} \over {{a^2}}} - {{{y^2}} \over {{b^2}}} = 1H:a2x2−b2y2=1 be 52\sqrt {{5 \over 2}}25 and length of its latus rectum be 626\sqrt 262. If y=2x+cy = 2x + cy=2x+c is a tangent to the hyperbola H, then the value of c² is equal to :A18B20C24D32Check answerSkip