MathematicsMedium64×since 2002Q2900Let the number (22)2022+(2022)22(22)^{2022}+(2022)^{22}(22)2022+(2022)22 leave the remainder α\alphaα when divided by 3 and β\betaβ when divided by 7. Then (α2+β2)\left(\alpha^{2}+\beta^{2}\right)(α2+β2) is equal to :A13B10C20D5Check answerSkip