Let the plane ax + by + cz = d pass through (2, 3, 5) and is perpendicular to the planes
2x + y 5z = 10 and 3x + 5y 7z = 12. If a, b, c, d are integers d > 0 and gcd (|a|, |b|, |c|, d) = 1, then the value of a + 7b + c + 20d is equal to :
JEE Main 2022 · 28 Jun, Evening shift · Q2590