MathematicsMedium249×since 2002Q2440Let x−23=y+1−2=z+3−1{{x - 2} \over 3} = {{y + 1} \over { - 2}} = {{z + 3} \over { - 1}}3x−2=−2y+1=−1z+3 lie on the plane px−qy+z=5px - qy + z = 5px−qy+z=5, for some p, q ∈\in∈ R. The shortest distance of the plane from the origin is :A3109\sqrt {{3 \over {109}}}1093B5142\sqrt {{5 \over {142}}}1425C571{5 \over {\sqrt {71} }}715D1142{1 \over {\sqrt {142} }}1421Check answerSkip