Let x^k + y^k = a^k, (a, k > 0 ) and …, then k is:

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Differentiation

JEE Main 2020 · 7 Jan, Morning shift · Q3669

MathematicsEasy63×since 2002Q3669

Let x^k + y^k = a^k, (a, k > 0 ) and

{{dy} \over {dx}} + {\left( {{y \over x}} \right)^{{1 \over 3}}} = 0

, then k is:

JEE Main 2020 · 7 Jan, Morning shift · Q3669

MathematicsEasy63×since 2002Q3669

Let x^k + y^k = a^k, (a, k > 0 ) and

{{dy} \over {dx}} + {\left( {{y \over x}} \right)^{{1 \over 3}}} = 0

, then k is: