Let y = y(x) be the solution curve of the differential equation, …, satisfying y(0) = 1. This curve intersects the x-axis at a point whose abscissa is :

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Differential Equations

JEE Main 2020 · 7 Jan, Evening shift · Q3602

MathematicsMedium38×since 2002Q3602

Let y = y(x) be the solution curve of the differential equation,

\left( {{y^2} - x} \right){{dy} \over {dx}} = 1

, satisfying y(0) = 1. This curve intersects the x-axis at a point whose abscissa is :

JEE Main 2020 · 7 Jan, Evening shift · Q3602

MathematicsMedium38×since 2002Q3602

Let y = y(x) be the solution curve of the differential equation,

\left( {{y^2} - x} \right){{dy} \over {dx}} = 1

, satisfying y(0) = 1. This curve intersects the x-axis at a point whose abscissa is :