MathematicsMedium38×since 2002Q3597Let y = y(x) be the solution of the differential equation, xy'- y = x²(xcosx + sinx), x > 0. if y (π\piπ) = π\piπ then y′′(π2)+y(π2)y''\left( {{\pi \over 2}} \right) + y\left( {{\pi \over 2}} \right)y′′(2π)+y(2π) is equal to :A1+π21 + {\pi \over 2}1+2πB2+π2+π242 + {\pi \over 2} + {{{\pi ^2}} \over 4}2+2π+4π2C2+π22 + {\pi \over 2}2+2πD1+π2+π241 + {\pi \over 2} + {{{\pi ^2}} \over 4}1+2π+4π2Check answerSkip