MathematicsMedium38×since 2002Q3525Let y = y(x) be the solution of the differential equation cosxdydx{{dy} \over {dx}}dxdy + 2ysinx = sin2x, x ∈\in∈ (0,π2)\left( {0,{\pi \over 2}} \right)(0,2π). If y(π3)\left( {{\pi \over 3}} \right)(3π) = 0, then y(π4)\left( {{\pi \over 4}} \right)(4π) is equal to :A12−1{1 \over {\sqrt 2 }} - 121−1B2−2{\sqrt 2 - 2}2−2C2−2{2 - \sqrt 2 }2−2D2+2{2 + \sqrt 2 }2+2Check answerSkip