MathematicsEasy179×since 2002Q4251limx→0(3x2+27x2+2)1x2\mathop {\lim }\limits_{x \to 0} {\left( {{{3{x^2} + 2} \over {7{x^2} + 2}}} \right)^{{1 \over {{x^2}}}}}x→0lim(7x2+23x2+2)x21 is equal toAeBe²C1e2{1 \over {{e^2}}}e21D1e{1 \over e}e1Check answerSkip