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Limits Continuity and Differentiability

JEE Main 2014 · Session, Shift 1 · Q4268

MathematicsMedium179×since 2002Q4268

\mathop {\lim }\limits_{x \to 0} {{\sin \left( {\pi {{\cos }^2}x} \right)} \over {{x^2}}}

is equal to :

JEE Main 2014 · Session, Shift 1 · Q4268

MathematicsMedium179×since 2002Q4268

\mathop {\lim }\limits_{x \to 0} {{\sin \left( {\pi {{\cos }^2}x} \right)} \over {{x^2}}}

is equal to :

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