Limits Continuity and Differentiability

JEE Main 2018 · 15 Apr, Evening shift · Q4272

MathematicsMedium179×since 2002Q4272

\mathop {\lim }\limits_{x \to 0} {{x\tan 2x - 2x\tan x} \over {{{\left( {1 - \cos 2x} \right)}^2}}}

equals :

JEE Main 2018 · 15 Apr, Evening shift · Q4272

MathematicsMedium179×since 2002Q4272

\mathop {\lim }\limits_{x \to 0} {{x\tan 2x - 2x\tan x} \over {{{\left( {1 - \cos 2x} \right)}^2}}}

equals :

More on Limits Continuity and Differentiability