MathematicsMedium64×since 2002Q3012n−1Cr=(k2−8)nCr+1{ }^{n-1} C_r=\left(k^2-8\right){ }^n C_{r+1}n−1Cr=(k2−8)nCr+1 if and only if :A22<k<232 \sqrt{2}<\mathrm{k}<2 \sqrt{3}22<k<23B22<k≤32 \sqrt{2}<\mathrm{k} \leq 322<k≤3C23<k<332 \sqrt{3}<\mathrm{k}<3 \sqrt{3}23<k<33D23<k≤322 \sqrt{3}<\mathrm{k} \leq 3 \sqrt{2}23<k≤32Check answerSkip