MathematicsMedium38×since 2002Q3651Suppose the solution of the differential equation dydx=(2+α)x−βy+2βx−2αy−(βγ−4α)\frac{d y}{d x}=\frac{(2+\alpha) x-\beta y+2}{\beta x-2 \alpha y-(\beta \gamma-4 \alpha)}dxdy=βx−2αy−(βγ−4α)(2+α)x−βy+2 represents a circle passing through origin. Then the radius of this circle is :A17\sqrt{17}17B2C172\frac{\sqrt{17}}{2}217D12\frac{1}{2}21Check answerSkip