MathematicsMedium202×since 2002Q5739 Let a⃗=2i^−j^+5k^ and b⃗=αi^+βj^+2k^. If ((a⃗×b⃗)×i^)⋅k^=232, then ∣b⃗×2j^∣\text { Let } \vec{a}=2 \hat{i}-\hat{j}+5 \hat{k} \text { and } \vec{b}=\alpha \hat{i}+\beta \hat{j}+2 \hat{k} \text {. If }((\vec{a} \times \vec{b}) \times \hat{i}) \cdot \hat{k}=\frac{23}{2} \text {, then }|\vec{b} \times 2 \hat{j}| Let a=2i^−j^+5k^ and b=αi^+βj^+2k^. If ((a×b)×i^)⋅k^=223, then ∣b×2j^∣ is equal to :A4B5C21\sqrt{21}21D17\sqrt{17}17Check answerSkip