MathematicsMedium110×since 2002Q3872The absolute minimum value, of the function f(x)=∣x2−x+1∣+[x2−x+1]f(x)=\left|x^{2}-x+1\right|+\left[x^{2}-x+1\right]f(x)=x2−x+1+[x2−x+1], where [t][t][t] denotes the greatest integer function, in the interval [−1,2][-1,2][−1,2], is :A34\frac{3}{4}43B32\frac{3}{2}23C14\frac{1}{4}41D54\frac{5}{4}45Check answerSkip