PhysicsHard159×since 2002Q7166The acceleration due to gravity at height hhh above the earth if h<<Rh << \mathrm{R}h<<R (Radius of earth) is given byAg′=g(1−2hR)g^{\prime}=g\left(1-\frac{2 h}{R}\right)g′=g(1−R2h)Bg′=g(1−2h2R2)g^{\prime}=g\left(1-\frac{2 h^{2}}{R^{2}}\right)g′=g(1−R22h2)Cg′=g(1−h22R2)g^{\prime}=g\left(1-\frac{h^{2}}{2 R^{2}}\right)g′=g(1−2R2h2)Dg′=g(1−h2R)g^{\prime}=g\left(1-\frac{h}{2 R}\right)g′=g(1−2Rh)Check answerSkip