MathematicsHard94×since 2002Q2832The area (in sq. units) of the part of the circle x² + y² = 36, which is outside the parabola y² = 9x, is :A12π−3312\pi - 3\sqrt 312π−33B24π+3324\pi + 3\sqrt 324π+33C24π−3324\pi - 3\sqrt 324π−33D12π+3312\pi + 3\sqrt 312π+33Check answerSkip