MathematicsHard92×since 2002Q4708The area (in sq. units) of the smaller of the two circles that touch the parabola, y^2 = 4x at the point (1, 2) and the x-axis is :-A4π(3+2)4\pi \left( {3 +\sqrt 2 } \right)4π(3+2)B8π(2−2)8\pi \left( {2 - \sqrt 2 } \right)8π(2−2)C8π(3−22)8\pi \left( {3 - 2\sqrt 2 } \right)8π(3−22)D4π(2−2)4\pi \left( {2 - \sqrt 2 } \right)4π(2−2)Check answerSkip