MathematicsHard94×since 2002Q2807The area (in sq. units) of the smaller portion enclosed between the curves, x² + y² = 4 and y² = 3x, is :A123+π3{1 \over {2\sqrt 3 }} + {\pi \over 3}231+3πB13+2π3{1 \over {\sqrt 3 }} + {{2\pi } \over 3}31+32πC123+2π3{1 \over {2\sqrt 3 }} + {{2\pi } \over 3}231+32πD13+4π3{1 \over {\sqrt 3 }} + {{4\pi } \over 3}31+34πCheck answerSkip