ChemistryEasy158×since 2002Q893The correct order of basicity of oxides of vanadium is :AV2O3>V2O5>V2O4\mathrm{V_2O_3 > V_2O_5 > V_2O_4}V2O3>V2O5>V2O4BV2O3>V2O4>V2O5\mathrm{V_2O_3 > V_2O_4 > V_2O_5}V2O3>V2O4>V2O5CV2O5>V2O4>V2O3\mathrm{V_2O_5 > V_2O_4 > V_2O_3}V2O5>V2O4>V2O3DV2O4>V2O3>V2O5\mathrm{V_2O_4 > V_2O_3 > V_2O_5}V2O4>V2O3>V2O5Check answerSkip