MathematicsMedium249×since 2002Q2425The distance of the point (1, 1, 9) from the point of intersection of the line x−31=y−42=z−52{{x - 3} \over 1} = {{y - 4} \over 2} = {{z - 5} \over 2}1x−3=2y−4=2z−5 and the plane x + y + z = 17 is :A19219\sqrt 2192B2192\sqrt {19}219C38D38\sqrt {38}38Check answerSkip