PhysicsEasy120×since 2002Q6808The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by Ex=Eosin(kz−ωt)\mathrm{{E_x} = {E_o}\sin (kz - \omega t)}Ex=Eosin(kz−ωt) By=Bosin(kz−ωt)\mathrm{{B_y} = {B_o}\sin (kz - \omega t)}By=Bosin(kz−ωt) Then the correct relation between E0_00 and B0_00 is given byAEoBo=ωk\mathrm{{E_o}{B_o} = \omega k}EoBo=ωkBE0=kB0\mathrm{{E_0} = k{B_0}}E0=kB0CkE0=ωB0\mathrm{k{E_0} = \omega {B_0}}kE0=ωB0DωE0=kB0\mathrm{\omega {E_0} = k{B_0}}ωE0=kB0Check answerSkip