MathematicsMedium129×since 2002Q5103The equation e4x+8e3x+13e2x−8ex+1=0,x∈R\mathrm{e}^{4 x}+8 \mathrm{e}^{3 x}+13 \mathrm{e}^{2 x}-8 \mathrm{e}^{x}+1=0, x \in \mathbb{R}e4x+8e3x+13e2x−8ex+1=0,x∈R has :Atwo solutions and both are negativeBtwo solutions and only one of them is negativeCfour solutions two of which are negativeDno solutionCheck answerSkip