PhysicsEasy100×since 2002Q8167The equation of a particle executing simple harmonic motion is given by x=sinπ(t+13)mx = \sin \pi \left( {t + {1 \over 3}} \right)mx=sinπ(t+31)m. At t = 1s, the speed of particle will be (Given : π\piπ = 3.14)A0 cm s^−-−1B157 cm s^−-−1C272 cm s^−-−1D314 cm s^−-−1Check answerSkip