MathematicsMedium249×since 2002Q2394The equation of the plane containing the line 2x−5y+z=3;x+y+4z=5,2x-5y+z=3; x+y+4z=5,2x−5y+z=3;x+y+4z=5, and parallel to the plane, x+3y+6z=1,x+3y+6z=1,x+3y+6z=1, is :Ax+3y+6z=7x+3y+6z=7x+3y+6z=7B2x+6y+12z=−132x+6y+12z=-132x+6y+12z=−13C2x+6y+12z=132x+6y+12z=132x+6y+12z=13Dx+3y+6z=−7x+3y+6z=-7x+3y+6z=−7Check answerSkip