MathematicsMedium128×since 2002Q5594The equation of the straight line passing through the point (4,3)(4, 3)(4,3) and making intercepts on the co-ordinate axes whose sum is −1-1−1 is :Ax2−y3=1{x \over 2} - {y \over 3} = 12x−3y=1 and x−2+y1=1{x \over -2} +{y \over 1} = 1−2x+1y=1Bx2−y3=−1{x \over 2} - {y \over 3} = -12x−3y=−1 and x−2+y1=−1{x \over -2} +{y \over 1} = -1−2x+1y=−1Cx2+y3=1{x \over 2} + {y \over 3} = 12x+3y=1 and x2+y1=1{x \over 2} +{y \over 1} = 12x+1y=1Dx2+y3=−1{x \over 2} + {y \over 3} = -12x+3y=−1 and x−2+y1=−1{x \over -2} +{y \over 1} = -1−2x+1y=−1Check answerSkip