The equilibrium constant for the reversible reaction 2A(g) … 2B(g) + C(g) is K₁ …A(g) … …B(g) + …C(g) is K₂. K₁ and K₂ are related as :

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Chemical Equilibrium

JEE Main 2022 · 30 Jun, Morning shift · Q421

ChemistryEasy49×since 2002Q421

The equilibrium constant for the reversible reaction 2A(g)

\rightleftharpoons

2B(g) + C(g) is K₁

{3 \over 2}

A(g)

\rightleftharpoons

{3 \over 2}

B(g) +

{3 \over 4}

C(g) is K₂. K₁ and K₂ are related as :