MathematicsMedium210×since 2002Q3381The integral ∫π6π3tan3x.sin23x(2sec2x.sin23x+3tanx.sin6x)dx\int\limits_{{\pi \over 6}}^{{\pi \over 3}} {{{\tan }^3}x.{{\sin }^2}3x\left( {2{{\sec }^2}x.{{\sin }^2}3x + 3\tan x.\sin 6x} \right)dx}6π∫3πtan3x.sin23x(2sec2x.sin23x+3tanx.sin6x)dx is equal to:A−19- {1 \over {9}}−91B−118- {1 \over {18}}−181C718{7 \over {18}}187D92{9 \over 2}29Check answerSkip